Two boxes of fruit on a friction less horizontal surface are connected by a ligh
ID: 1443862 • Letter: T
Question
Two boxes of fruit on a friction less horizontal surface are connected by a light string as in the figure below, where m_1 = 12 kg and m_2 = 22 kg. A force of F = 66 N IS applied to the 22-kg block. Determine the acceleration of each block and the tension In the string. Repeat the problem for the case where the coefficient of kinetic fnction between each block and the surface is 0.10. A 81-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining us maximum speed of 1.2 m/s in 0.78 s. The elevator travels with this constant speed for 5.0 s, undergoes a uniform negative acceleration for 1.5 s. and then comes to rest. What does the spnng scale register in each of the following time intervals? before the elevator starts to move during the first 0.78 s of the elevator's ascent while the elevator is traveling at constant speed I during the elevator's negative accelerationExplanation / Answer
m1 = 12 Kg
m2 = 22 Kg
F = 66 N
(a)
Acceleration, a
F = (m1 + m2) * a
a = F/(m1 + m2)
a = 66/(12 + 22)
a = 1.94 m/s^2
Acceleration of Block m1, a = 1.94 m/s^2
(b)
Acceleration of Block m2, a = 1.94 m/s^2
(c)
Tension in the String, T = m2*a
T = 12 * 1.94 N
T = 23.3 N
2)
(a)
ug = 0.10
F - (m1 + m2)*uk*g = (m1+m2)*a
a = (66 - 0.1*9.8*(12+22))/(12 + 22)
a = 0.96 m/s^2
Acceleration of Block m1, a = 0.96 m/s^2
(b)
Acceleration of Block m2, a = 0.96 m/s^2
(c)
Tension in the String, T = uk*m1*g + m1*a
T =0.1*12*9.8 + 12*0.96
T = 23.3 N
Please post seperate questions in seperate post.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.