This is the beginning of the question. A 2.40-cm-high insect is 1.10 m from a 12

Question

This is the beginning of the question.

A 2.40-cm-high insect is 1.10 m from a 121-mm-focal-length lens. Where is the image? Follow the sign conventions.

I have found the answer for this part, but then it goes onto say...

D. Where is the image of the insect if the focal length of the lens is f=121mm? Follow the sign conventions.

E. How high is the image of the insect if the focal length of the lens is f=121mm? Follow the sign conventions.

F. What type is the image of the insect if the focal length of the lens is f=121mm?

(a). virtual upright

(b). real, inverted

(c). real, upright

(d). virtual, inverted

Explanation / Answer

D)

do = object distance = 1.10 m

di = image distance

f = focal length = - 0.121 m

using the lens equation

1/di + 1/do = 1/f

1/di + 1/1.10 = 1/(-0.121)

di = - 0.109 m

E)

using the magnification equation

hi/ho = - di/do

hi / 2.40 = - (-0.109) / 1.10

hi = 0.238 m

F)

virtual , upright

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