A solid metal sphere of radius a= 1.30 cm is surrounded by a concentric spherica

Question

A solid metal sphere of radius a= 1.30 cm is surrounded by a concentric spherical metal shell of inner radius b= 2.40 cm and outer radius c= 2.90 cm. The inner sphere has net charge Ql= 3.40 micro C, and the outer spherical shell has net charge Q2= -8.60 micro C. (For reference see class notes) What is the radial component of the electric field E_r at a point located at radius r= 2.10 cm, i.e. between the two conductors? (E_r is positive if E points outward, negative if E points inward.) What is E_r at a point located at radius r= 3.30 cm, i.e. outside the outer shell?

Explanation / Answer

4) a =1.3 cm , b =2.4 cm , c = 2.9 cm, Q1 =3.4 uC, Q2 = -8.6 uC

for r =2.1 cm

From Gauss law E.A = Qinside/eo

E(4pi*r^2) = Q1/eo

E (4*3.14*2.1*2.1*10^-4)= (3.4*10^-6)/(8.85*10^-12)

E= 6.94*10^7 N/C

for r=3.3 cm

E(4pi*r^2) = (Q1-Q2)/eo

E(4*3.14*3.3*3.3*10^-4) = (3.4 - 8.6)*10^-6/(8.85*10^-12)

E = -4.3 *10^7 N/C

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