A mass m 1 = 4.2 kg rests on a frictionless table and connected by a massless st

Question

A mass m1 = 4.2 kg rests on a frictionless table and connected by a massless string to another mass m2 = 4.1 kg. A force of magnitude F = 26 N pulls m1 to the left a distance d = 0.73 m.

1)

How much work is done by the force F on the two block system?

J

2)

How much work is done by the normal force on m1 and m2?

J

3)

What is the final speed of the two blocks?

m/s

4)

How much work is done by the tension (in-between the blocks) on block m2?

J

5)

What is the tension in the string?

N

6)

The net work done by all the forces acting on m1 is:

positive

zero

negative

7)

What is the NET work done on m1?

J

Explanation / Answer

v^2 = 2*3.13*0.73
v = 2.14 m/s

4) the tension is
T = m2*a = 4.1*3.13 N = 12.8 N
Work = tension*distance = T*s = 12.8*0.73 Nm = 9.37 Nm

5) see 4)

6) there are two forces on m1 that do work: F and T:
work by F = F*s = 26*0.73 Nm
work by T = - 12.8*0.73 Nm ( opposite direction of T vs. F)

7) Net work = (F - T)*s = (26 – 12.8)*0.73 = 9.636 J

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