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-2 South Carolina State... Hb Videos- P255-01-SP...Outside Assig South Carolina S...x o 3/16/2016 09:55 PM 839/1003/16/2016 08:44 PM Print Calculator-d Periodic Table Gra Question 13 of 13 Map You have two capacitors, one with capacitance 13.3 × 10 F and the other of unknown capacitance. You connect the two capacitors in series with a voltage difference of 361 V a across the capacitors. You discover that, as a result, the unknown capacitor has a charge of 0.00167 C. Find its capacitance. Number -8 Exit Check Answer Previous Hint

Explanation / Answer

given data is capacitance C1=13.3*10-6F,charge q=167*10-5c ,V=361 v

here capacitors are connected in series then resultant capacitance C=13.3*10-6*C2/13.3*10-6+C2

charge q=cV

167*10-5=(13.3*10-6*C2/13.3*10-6+C2)*361

C2=7.09*10-6F

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