-12 points SerPSET9 29.P033. My Notes A8k Your Tea? A conductor carrying a curre

Question

-12 points SerPSET9 29.P033. My Notes A8k Your Tea? A conductor carrying a current I 16.5 A is directed along the positive x axis and perpendioular to a uniform magnetic field. A magnetic force per unit length of 0.115 N/m acts on the conductor in the negative y direction. (a) Determine the magnitude of the magnetic field in the region through which the current passes. (b) Determine the direction of the magnetic field in the region through which the current passes. +x direction O -xdirection o ty direction y direction O +z direction O -z direction o -

Explanation / Answer

Magnetic force is given by:

F = i*LxB

F = i*L*B*sin theta

theta = 90 deg = Angle between current and magnetic field

Sin 90 deg = 1

F = i*L*B

given that

F/L = Force per unit length = 0.115 N/m (-j)

B = F/(L*i)

B = 0.115/(16.5) = 6.97*10^-3 T

Part B

LxB is gives direction of F & L and B are perpendicular,

F = F(-j)

L = L(+i)

B Should be in +k direction, (So that LxB = ixk = -j), So that Force can be in -ve y direction

Direction of B = +z direction

Please Upvote.

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.