In the picture below, the two wires carry current i1 and i2, respectively, with

Question

In the picture below, the two wires carry current i1 and i2, respectively, with positive current to the right. The charge q is positive and has velocity v to the right. If i2 = 0 and i1 is greater than zero, then the force on q is north. If i1 = - i2, then the wires repel each other. If i2 = - i1 then the force on q equals zero. If i1 = 0 and i2 is greater than zero, then the magnetic field near charge q points into the page. If i1 = 0 and i2 is greater than zero, then the force on q points out of the page. If i1 is greater than i2, then the force on q is north. If v = 0, then the force on q is zero.

Explanation / Answer

Answer:

As q is a positive charge, then we use the right hand rule.

we can determine the direction of the magnetic field due to the wires using the right hand rule.

1. If i2 = 0 and i1 is greater than zero, then the force on q is north.

TRUE. B is into the page. Thus, Force is due NORTH.

2. If i1 = - i2, then the wires repel each other.

TRUE. Wires of opposite currents repel.

3. If i2 = - i1 then the force on q equals zero.

FALSE. The magnetic field at the middle even becomes stronger in this case, and hence the force.

4. If i1 = 0 and i2 is greater than zero, then the magnetic field near charge q points into the page

True

5.  If i1 = 0 and i2 is greater than zero, then the force on q points out of the page.

False, force is southward

6. If i1 is greater than i2, then the force on q is north

TRUE. This is similar with number 1.

7. If v = 0, then the force on q is zero.

True, V becomes zero, so force is zero

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