A region of space has an electric field of 905 N/C in the +x direction, and a ma

Question

A region of space has an electric field of 905 N/C in the +x direction, and a magnetic field of I 60 T m the direction (a) If at a particular instant a 2.75 muC charged particle moving in the x-y plane experiences a net force of 4 35 x 10 N. purely in the +x direction, what is the speed and direction of the charged particle at that instant'' Include a diagram (use the notation for vectors pointing in or out of the page as necessary) (b) What would the net force on the particle be if its motion was instead toward the origin along the z-axis?

Explanation / Answer

The electric force acting on the charged particle is

F1 = qE = 2.75 * 10^-6 C ( 905) = 2.49 * 10^-3 N

the net force acting on the charge is

F net = F1 + F2 = 4.35 * 10^-3 N

F2 = F net - F1 =  4.35 * 10^-3 N -2.49 * 10^-3 N= 1.86 * 10^-3 N

The magnetic force on the charge is

F2 = qvB

1.86 * 10^-3 N= 2.75 * 10^-6 C v ( 1.6 T)

v = 422.73 m/s

by the right hand rule , the dirction of moving charged particle is along + y direction

(b)

on reversing velocity magnetic force will also reverse so net force is

F net = F1 - F2 = 2.49 * 10^-3 - 1.86 * 10^-3 = 0.63 * 10^-3 N along + x axis

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