A charge of -8.3 C is traveling at a speed of 7.4 x 10 6 m/s in a region of spac

Question

A charge of -8.3 C is traveling at a speed of 7.4 x 106 m/s in a region of space where there is a magnetic field. The angle between the velocity of the charge and the field is 52o. A force of magnitude 5.4 x 10-3 N acts on the charge. What is the magnitude of the magnetic field? Comment on the direction of the magnetic field.A charge of -8.3 C is traveling at a speed of 7.4 x 106 m/s in a region of space where there is a magnetic field. The angle between the velocity of the charge and the field is 52o. A force of magnitude 5.4 x 10-3 N acts on the charge. What is the magnitude of the magnetic field? Comment on the direction of the magnetic field.

Explanation / Answer

Magnitude of the force on teh cahrged particle moving through magnetic field is ,

F = Bqvsin (theta)

Solve for B

B = F / qvsin (theta)

B = 5.4*10^ -3 / (-8.3*10^-6 C) (7.4*10^6 m/s) sin(52) = 1.12 *10 ^-4 T

DIRECTION

52 degrees with velocity vector

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.