A bat strikes a 0.145-kg baseball. Just before impact, the ball is traveling hor

Question

A bat strikes a 0.145-kg baseball. Just before impact, the ball is traveling horizontally to the right at 40.0 m/s, and it leaves the bat traveling to the left at an angle of 40 degree above horizontal with a speed of 60.0 m/s. The ball and bat are in contact for 1.85 ms. Find the horizontal component of the average force on the ball. Take the x-direction to be positive to the right Express your answer using two significant figures. Find the vertical component of the average force on the ball. Express your answer using two significant figures.

Explanation / Answer

taking +ve x-direction to the right

ball leaves the bat with horizontal velocity Vh = -60*cos(40 degree) = -45.96 m/s

velocity before impact = 40 m/s

after impact acceleration of the ball a = dv/dt = (-45.96 - 40)/(1.85*10^-3) = -46.46*10^3 m/s^2

A) force exerted on ball in horizontal direction Fx = m*a = -0.145*46.46*10^3 = -6.73 kN

B) acceleration in vertical direction a = 60*sin(40 degree)/(1.85*10^-3) = 20.84*10^3 m/s^2

force exerted in vertical direction Fy = 0.145*20.84*10^3 = 3.02 kN

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