Question
please help! preferably with parts C-E
PROBLEM 3-10 points A wire loop measuring 4.0 m x 1.0 m is placed so exactly half the loop is in a uniform magnetic field. The field is into the page with a magnitude B-4.0The boundary of the field is the vertical line in the diagram. Assume the field extends vertically up and down the page, but does not extend to the right of the boundary. x xx X xX x X x | X X X e page, but does x xx 1.0 m 4.0 m [l point] (a) Calculate the magnetic flux through the loop. A Cos 14 points] (b) Determine the direction of the induced current in these situations: (i) The magnetic field is jncreased. The induced current is I -1 counter-clockwise ] zero (i) The wire loop is pulled to the right. The induced current is: I1 clockwise counter-clockwise 1zeno (ii) The wire loop is pulled up the page. The induced current is: I 1 clockwise counter-clockwise 1zero The loop is rotated with the boundary as the axis of rotation so that the left side starts to come up out of the paper. The induced current is: (iv) ['] clockwise counter-clockwise zero I2 nointsl (cl The welogn is then pulled to the iohp at constant speed. If the resistance of the loop is
Explanation / Answer
C. Let the constant speed be v
Induced emf = D(phi)/dt = d(BA)/dt = d(Blw)dt = Bw(dw/dt) = Bwv (where w is width of the loop)
V = Bwv
V = IR
Bwv = IR
v = IR/Bw = 2*5/4*1 = 2.5 m/s
D. Work = F*s
F = BIL = 2*4*1 = 8N
Work = 8*2 = 16J
E. For double velocity, we have double curent and hence double force, so double work
