A 3.00 F capacitor is charged to 480 V and a 3.55 F capacitor is charged to 500

Question

A 3.00 F capacitor is charged to 480 V and a 3.55 F capacitor is charged to 500 V .

Part A ( I already have part A)

These capacitors are then disconnected from their batteries, and the positive plates are now connected to each other and the negative plates are connected to each other. What will be the potential difference across each capacitor?

491,491

Part B

What will be the charge on each capacitor?

Enter your answers numerically separated by a comma.

Part C

What is the voltage for each capacitor if plates of opposite sign are connected?

Express your answers using two significant figures. Enter your answers numerically separated by a comma.

Part D

What is the charge on each capacitor if plates of opposite sign are connected?

Express your answers using two significant figures. Enter your answers numerically separated by a comma.

491,491

Explanation / Answer

Part A)   Here, initial charge = final charge

=> 3 * 480 + 3.55 * 500 = (3 + 3.55) * V

=> V =   491 V     ---------------> the potential difference across each capacitor

Part B)    charge on first capacitor   = 491 * 3

                                                          = 1473   C

           => charge on second capacitor   = 491 * 3.55

                                                          = 1743.05 C

Part C)    Here,   - 3 * 480 + 3.55 * 500 = (3 + 3.55) * V

       => V =   51.145 V       ---------------------->   voltage for each capacitor

Part D )     charge on first capacitor   = 51.145 * 3

                                                          = 153.435 C

           => charge on second capacitor   = 51.145 * 3.55

                                                          = 181.56 C

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