A tennis ball connected to a string is spun around in a vertical, circular path

Question

A tennis ball connected to a string is spun around in a vertical, circular path at a uniform speed. The ball has a mass m = 0.169 kg and moves at v = 5 m/s. The circular path has a radius of R = 1.01 m

1)

What is the magnitude of the tension in the string when the ball is at the bottom of the circle?

N

2)

What is the magnitude of the tension in the string when the ball is at the side of the circle?

N

3)

What is the magnitude of the tension in the string when the ball is at the top of the circle?

N

4)

What is the minimum velocity so the string will not go slack as the ball moves around the circle?

m/

Explanation / Answer

given datais mass m=0.169kg,V=5m/s,R=1.01m

1) the magnitude of the tension in the string when the ball is at the bottom of the circle is T=(mv2/R)+mg

T=(0.169*52/1.01)+0.169*9.8=5.83N

2) the magnitude of the tension in the string when the ball is at the side of the circle T=mv2/R

T=(0.169*52/1.01)=4.18N

3)

the magnitude of the tension in the string when the ball is at the top of the circle T=(mv2/R)-mg

T=(0.169*52/1.01)-0.169*9.8=2.52N

4)minimum velocity of the string v=root(rg)=root(1.01*9.8)=3.14m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.