A solar cell generates a potential difference of 1.62 V when a 1.50 k external r

Question

A solar cell generates a potential difference of 1.62 V when a 1.50 k external resistance is connected across it, i.e., from one terminal of the cell to the other terminal of it, and a potential difference of 1.84 V when a 2.70 k external resistance is used. What is the internal resistance ri of the solar cell? (Give your answer in the form of "abc" .) (Hint: Think of the solar cell as a non-ideal, i.e., real, battery, as discussed in class. Assume that the ideal emf source E(V) and the internal resistance ri are not affected by the external resistance that is connected across the solar cell.)

Explanation / Answer

1.62 = E - i1 ri

1.62 = E - (1.62/1500) ri

1.62 = E - 0.00108 ri

==> E = 1.62 + 0.00108 ri

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1.84 = E - i1 ri

1.84 = E - (0.0006.815) ri

1.84 = E - 0.0006.815 ri

1.84 = (1.62 + 0.00108 ri) - 0.0006.815 ri

==> (0.00108 - 0.0006.815) ri = 1.84 - 1.62

==> ri = 552 ohms

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