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#1a: An electrical current of 6.50 mA exists in a solid cylindrical wire whose d

ID: 1435066 • Letter: #

Question

#1a: An electrical current of 6.50 mA exists in a solid cylindrical wire whose diameter is 1.50 mm. Calculate the magnitude of the current density in the wire. Put your answer in the form of "a.bc x 10^(x)" A/m2.

#1b: Assume that electrons are the charge carriers and the conduction electron density is 4.55 x 1029/m3. (Note that this is the charge carrier density and could also be stated as 4.55 x 1029 charge carriers/m3 or electrons/m3.) Calculate the electron drift speed in the wire. Put your answer in the form of "a.bc x 10^(x) m/s".

Explanation / Answer

#1a : electrical current = 6.50 mA = 6.50 * 10-3 A

         diameter is = 1.50 mm

    Cross section Area = 3.14*(1.50/2)2 = 1.77 mm2 = 1.77 * 10-6 m2

the magnitude of the current density in the wire = 3.68 * 103 A/m2

.#1b:

the conduction electron density is 4.55 x 1029/m3

electron drift speed in the wire = V

     neAV = Current

or    4.55 x 1029*1.6*10-19* 1.77 * 10-6*V = 6.50 * 10-3

or          V = 5.25 * 10-8 m/s