#17. Suppose a basketball player has a 72% success rate for shooting free throws
ID: 3147602 • Letter: #
Question
#17. Suppose a basketball player has a 72% success rate for shooting free throws what is/determine the probability that the player will succeed at least two times out of the next three free throw attempts. Sw Tree diagram suggested #18: Two 5-card hands are dealt to two players. Suppose the first player happens to get exactly two aces, no more,no less. Given that the first player now has exactly two aces, calculate the conditional probability that the second player gets exactly two aces, no more/no less, as well. SW 496] [Note: P(l" gets exactly 2 aces) CCsCs) -out of page total: out of cumulative total: #19: Suppose one pays s0.00. Determine how much aces should return so that the game is a fair game, that is, the expected value is S0.00. This uses an ordinary 52-card deck with 12 face cards, 4 aces, and 36 other cards, SW #10 to play a card game in which a face card returns $20 and other non-aces return nothing,
Explanation / Answer
17.
p = 0.72
P(X = 2) = 3C1 * p^2 * (1-p) = 3 * 0.72^2 * (1-0.72) = 0.4355
P(X = 3) = p^3 = 0.72^3 = 0.3733
Required probability = 0.4355 + 0.3733 = 0.8088
18)
P(1st gets exactly 2 aces) = 4C2 * 48C3 / 52C5 = 0.0399
P(2nd gets exactly 2 aces | 1st gets exactly 2 aces) = 2C2 * 45C3 / 48C5 = 0.00828708
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