Unpolarized light with initial intensity of I_o goes through two linear polarize

Question

Unpolarized light with initial intensity of I_o goes through two linear polarizers. The first polarizer has a transmission axis at an angle of +45 degree with respect to the vertical and the second polarizer has a transmission axis at an angle of +60 degree with respect to the vertical. What is the final intensity of light? 0.500 I_o 0.467 I_o 0.250 I_o 0.125 I_o 0 If a third polarizer with a transmission axis at an angle of +90 degree to the vertical, where should it be placed to maximize the intensity the of transmitted light? Before the first polarizer between the polarizers after the second polarizer where should this third polarizer be placed to minimize the intensity of transmitted light? before the first polarizer between the polarizers after the second polarizer

Explanation / Answer

28) I = I0 x (1/2) x cos2(60-45) = 0.467 I0 option (b)

29) let the polarizers be 1,2,3 from left to right. and A is angle made by them with vertical line

now I = I0 x (1/2) x cos2(A2-A1) x cos2(A3-A2) = max when the 3rd polarizer with A = 90 is after the second polarizer. and then I = I0 x (1/2) x cos2(15) x cos2(30) = 0.35 I0 option C

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