1. Normal saline contains 154 mEq/L. Your patient required 1.5 L of normal salin
ID: 143479 • Letter: 1
Question
1. Normal saline contains 154 mEq/L. Your patient required 1.5 L of normal saline. How many grams of NaCl did your patient receive? (MW of NaCl- 58.4 g/mol) a) 6.0 g NaCl b) 6.7 g NaCl c) 9.0 g NaCl d) 13.5 g NaCl 2. As a general rule of thumb, 10 mEq of potassium will raise a patient's serum potassium level by 0.1. If your patient has a serum potassium level of 3.2 (normal is 3.5), how many milligrams of KCl must you give to rectify your patient's serum potassium? (MW of KCI-74.5 g/mol) Hint: How many mEq will it take to increase the patient's serum potassium from 3.2 to 3.5? a) 22 mg KCI b) 1118 mg KCl c) 1490 mg KCl d) 2235 mg KCIExplanation / Answer
ANSWER 1) 13.5 gram NaCl
Explanation
Normal saline contains = 154mEq/Litre or 154 milli Mole
1.5Litre of saline given to patient.
Molecular weight of NaCl = 58.4 g/mol
Grams of NaCl the patient received = No. of Grams of Nacl in 1.5litre
NO. of grams of NaCl in 1 litre Normal saline = 154 milli mole X 58.4 g/mol
= .154 x 58.4g/ mol
= 9 gm
No. of Grams of NaCl in 1.5litre = 1.5 x 9
ANSWER = 13.5 grams
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ANSWER 2) d-2235 mg KCL
EXPLANATION
10mEq of potassium will raise a patient’s serum by 0.1
Patients serum level =3.2
Normal level = 3.5
Serum needs to be raised by = 3.5 - 3.2 =0.3
How much potassium will be needed to raise 0.3 serum = 10mEq X 3= 30 mEq
Given Molecular weight of KCl=74.5g/mol
No. of milligrams of KCl required = 30mEq X 74.5g/mol
= 30 mM X 74.5 g/mol
Answer = 2235 mg KCL
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