A geostationary communications satellite orbits the earth directly above the equ
ID: 1433103 • Letter: A
Question
A geostationary communications satellite orbits the earth directly above the equator at an altitude of35600 km .
Part A
Calculate the time it would take a cell phone signal to travel from a point on the equator to the satellite and back.
Express your answer to three significant figures with the appropriate units.
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Part B
Would this delay be noticeable in a conversation?
A geostationary communications satellite orbits the earth directly above the equator at an altitude of35600 km .
Part A
Calculate the time it would take a cell phone signal to travel from a point on the equator to the satellite and back.
Express your answer to three significant figures with the appropriate units.
t =SubmitMy AnswersGive Up
Part B
Would this delay be noticeable in a conversation?
Would this delay be noticeable in a conversation? Yes NoExplanation / Answer
The distance between the transmitting and receiving points is 2 Re measured through the Earth.
Then the satellite is a distance (35600 + Re) above the centre point of the Earth
The distance to and from the satellite (D) is the hypotenuse of a right-angles triangle .. right-angled sides (Re) and (35600km + Re)
D² = Re² + (35600km + Re)²
D² = (6371km)² + (35600 + 6371km)² .. .. D = 42451.8 km
Total signal path = 2 x D .. .. 84903.6 km
Time taken = D/vel of light = 84903.6km / 3.0^5 km/s .. .. t = 0.28 s
NO it Would not delay
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