A spherical cavity of radius 4.50 cm is at the center of a metal sphere of radiu

Question

A spherical cavity of radius 4.50 cm is at the center of a metal sphere of radius 18.0 cm. A point charge Q = 6.10 µC rests at the very center of the cavity, whereas the metal conductor carries no net charge. Determine the electric field at the following points.

(a) 3.1 cm from the center of the cavity
N/C  --Direction-- away from the center of the sphere no direction toward the center of the sphere

(b) 5.0 cm from the center of the cavity

N/C  --Direction-- toward the center of the sphere away from the center of the sphere no direction

A spherical cavity of radius 4.50 cm is at the center of a metal sphere of radius 18.0 cm. A point charge Q = 6.10 µC rests at the very center of the cavity, whereas the metal conductor carries no net charge. Determine the electric field at the following points. 3.1 cm from the center of the cavity N/C --Direction-- away from the center of the sphere no direction toward the center of the sphere 5.0 cm from the center of the cavity N/C --Direction-- toward the center of the sphere away from the center of the sphere no direction

Explanation / Answer

a) taking a conectric sphere as Gaussian Surface,

now applying Gauss' LAw,

flux = E. A = Qinside / e0

E ( 4 pi 0.031^2) = (6.10 x 10^-6 ) / (8.854 x 10^-12)

E = 5.71 x 10^7 N/C

Direction : radially towards the charge

b) r = 5.0 cm

this point lies inside a conductor .

and field inside a conductor is zero .

hence E = 0

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