explain b and the rest of c Consider the system of capadtors shown in the figure

Question

explain b and the rest of c

Consider the system of capadtors shown in the figure below (C1 2.00 f, 6.00 the system of capacitors shown in the figure below (G 2.0n p , de-6.00. (a) Find the equivalent capacitance of the systerm UF (b) Find the charge on each capacitor pC (on C1) c (on the o.00 ge capaditor) (on the 2.00 iF capacitor) c) Find the potential dfteranca acroas each capacitor v(across Cal 20 67.b Yuur rai or a differs rom the correct answer by more than 100% v acrom the 6,00 uf capacitor) Double check your calculations V (acrass the Your response dirters from the correct answer by more tham 30 2.00 yF pacitor

Explanation / Answer

a) C1 and 6 uF are in series

equivalent of these two is C' then

1/C' = 1/C1 + 1/6 = 1/2 + 1/6

C' = 1.5 uF

capacitor in the lower branch also have same arrangement.

so equivalent of these two will also be 1.5 uF

now two 1.5uF are in paralllel connection.

Ceq = 1.5 + 1.5 = 3uF ....Ans

b) Q = Ceq V = 3 uF x 90 V = 270 uC

this charge wil get divided in both brnaches and series capacitors have same charge.

so this will divided in half in both branches as branches have same capacitance.

so Q1 = Q2 = Q(on 6uF ) = Q (on 2uF) = 270/2 = 135 uC

c) V1 = Q1/C1 = 135 uC / 2 uF = 67.5 V

V2 = Q2/C2 = 135 / 6uF = 22.5 V

V (across 6uF) = 135 / 6uF = 22.5 V

V(across 2 uF) = 135 uC / 2 uF = 67.5 V

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