questions 5-8 refer to the following circuit Questions 5-8 refer to the followin
ID: 1428412 • Letter: Q
Question
questions 5-8 refer to the following circuit
Explanation / Answer
Q5.
while finding resistance between two nodes, other nodes will be assumed to
be open circuited.
hence any free hanging resistance will not feature in resistance calculation
Rab:
resistance between a and b:
5 ohms and 6 ohms are free hanging resistors and hence wont be considered while finding resistance between a and b
now, 1 ohms, 3 ohms and 4 ohms are in series.
their equivalent resistance=1+3+4=8 ohms
8 ohms is in parallel with 2 ohms.
then net resistance=8*2/(8+2)=1.6 ohms
hene Rab=1.6 ohms
resistance between b and c:
only resistance that acts between b and c is 5 ohms
hence Rbc=5 ohms
resistance between c and d:
2 ohms,1 ohms and 3 ohms are in series.
their equivalent resistance=2+1+3=6 ohms
6 ohms is in parallel with 4 ohms
their equivalent resistance=6*4/(6+4)=2.4 ohms
2.4 ohms is in series with 5 ohms and 6 ohms
then net resistance=2.4+5+6=13.4 ohms
Rcd=13.4 ohms
resistance between d and e:
only resistance acting between d and e is 6 ohms
hence Rde=6 ohms
resistance between e and f:
5 ohms and 6 ohms will be ignored as they are free hanging resistors.
4 ohms, 2 ohms and 1 ohm are in series
their net resistance=4+2+1=7 ohms
it is in parallel with 3 ohms
then net resistance=7*3/(7+3)=2.1 ohms
hence Ref=2.1 ohms
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