question: A force acting on a 2.00 kg object is given by F(x) = (2.00 N/m) x + (

Question

question: A force acting on a 2.00 kg object is given by F(x) = (2.00 N/m) x + (1.00

N/m3) x3. The object stats at rest at x = 1.00 m. What is the speed of the object when it reaches x = 2.00 m?

Question1: A golf club exerts an average force of 1000 N on a 0.045-kg golf ball which is initially at rest. The club is in contact with the ball for 1.8 ms. What is the speed of the golf ball as it leaves the club?

Q3: ) A 2.00-m rod of negligible mass connects two small objects. The mass of one object is 1.00 kg and the mass of the other is unknown. The center of mass of this system is on the rod a distance 1.80 m from the 1.00-kg mass object. What is the mass of the other object?

Q4: A cyclist does work at the rate of 500 W while riding. How much force does her foot

push with when she is traveling at 8.0 m/s?

Q5: A mass of 2.0 kg traveling at 3.0 m/s along a smooth, horizontal plane hits a relaxed

spring. The mass is slowed to zero velocity when the spring has been compressed by 0.15 m. What is the spring constant of the spring?

Q6: The force on an object as a function of position is shown in the figure. Determine the

amount of work done by this force on an object that moves from x = 2.0 m to x = 7.0 m.

Q7: A force is dependent on position and is given by (4.00)xi+(2.00)xyj . An object begins

at the origin. It first moves in a straight line to x = 1.00 m, y = 0.00 m. It then moves in a straight line to x = 1.00 m, y = 1.00 m. How much work is done on the object by the force during the motion described?

Q8: A 600-kg car is going around a banked curve with a radius of 110 m at a speed of 27.5 m/s. What is the appropriate banking angle so that the car stays on its path without the assistance of friction?

: The two forces indicated in the figure act on a 3.00-kg object. What is the acceleration

of the object?

(a) (1.67 m/s2) i - (0.333 m/s2) j

(b) (5.00 m/s2) i + (1.00 m/s2) j

(c) (1.67 m/s2) i + (2.333 m/s2) j

(d) (15.0 m/s2) i + (3.00 m/s2) j

(e) (1.67 m/s2) i + (0.333 m/s2) j

Explanation / Answer

1. 40ms

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