As the angle of the ramp is increased, the normal force increases/decreases/rema

Question

As the angle of the ramp is increased, the normal force increases/decreases/remains the same and the friction force increases/decreases/remains the same 3. As the angle of the ramp is increased, the force parallel increases/decreases/remains the sane 4. The angle at which the force down the plane was equal to the force of friction was 5. Consider a very low (zero) friction, 5.0 kg skateboard on a ramp at an angle of 15 to the horizontal. what would be the net force that would cause acceleration when the skateboard is allowed to move? N 6. What would be the skateboard's acceleration down the plane? m/s^2 7. Now consider the same no-friction 5.0 Kg skateboard on the same 15 ramp. If a 45Kg teenager jumps on what would be her acceleration down the ramp

Explanation / Answer

Here,

2)

It decreases. If the ramp is horizontal, all we have is normal force. If the ramp is at 90 degrees, normal force is zero.By an equation (when theta is the angle above horizontal):

Fgravity = g*m
Fnormal = fgravity * cos(theta)

5)

F = mgsin(theta)

F = 5.0 * 9.8 * sin(15)
= 12.68 N directed down the slope

6)

a = 12.68/ 5 = 2.536 m/s^2

7)

a = 12.68/ 5 = 2.536 m/s^2

9)

Ff = u*m*g*costheta
Ff = 0.02*(15 + 25)9.8*cos15
Ff = 7.5728 N

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