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Begin Date: 2/26/2016 12:00:00 AM - Due Date: 3/2/2016 11:59:00 PM End Date: 3/2

ID: 1427927 • Letter: B

Question

Begin Date: 2/26/2016 12:00:00 AM - Due Date: 3/2/2016 11:59:00 PM End Date: 3/2/2016 11:59:00 PM Suppose a man stands in front of a mirror as shown in the figure. His eyes are 135 m above the floor, and the top of his head is 0.11 m higher. Randomized Variables h_c = 1.55 m h_h = 0.11 m Find the height above the floor of the bottom of the smallest mirror in which he can see both the top of his head and his feet. Find the height above the floor of the top of the smallest mirror in which he can see both the top of his head and his feet. h_t =

Explanation / Answer

Here,

he = 1.55 m

hh = 0.11 m

a)

For the height of the smallest mirror

as he sound be able to see his legs

and the angle of incidence = angle of reflection

hb * 2 = height of eyes

hb * 2 = 1.55

hb = 0.775 m

the height of the bottom of the smallest mirror is 0.775 m

b)

for the height of the top of the mirror

ht = hh + he/2

ht = 1.55 + 0.11/2

ht = 1.55 + 0.11/2

ht = 1.605 m

the height ht is 1.605 m

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