Question 19 A heat engine takes 2.9_mol of an ideal gas through the reversible c

Question

Question 19

A heat engine takes 2.9_mol of an ideal gas through the reversible cycle on the pV diagram shown in the figure. The path bc is an isothermal process. The temperature at c is 860_K, and the volumes at a and c are 0.018_m^3 and 0.014_m^3, respectively. The molar heat capacity at constant volume, of the gas, is C_V = 37_J/mol K, and the ideal gas constant is R = 8.314_J/mol K. Find the following values. P_A 174500_Pa 148100_Pa 105500_Pa 200200_Pa 241700_Pa 157600_Pa 1760000_Pa 1484000_Pa 1152000_Pa 1671000_Pa 708700_Pa 1271000_Pa 204_K 165.4_K 102.3_K 162.9_K 174.7_K 110.6_K eta [must still find works and heats) 21.1% 16.58% 18.02% 19.9% 37.51% 16.18%

Explanation / Answer

Pa = Pc

at c

Pc*Vc = n*R*Tc

Pa*0.14 = 2.9*8.314*860

Pa = 148100 pA

OPTION (B)

___________

17)

bC ISOTHERMAL PROCESS

pb*vb = pc*vc

Pb*0.018 = 141800*0.14

Pb = 1152000 Pa

___________

TA/VA = TC/Vc

TA/0.018 = 860/0.14

TA = 110.6 K

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