Question 18 of 25 1.0 Points Click to see additional instructions A Wendy\'s fas

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Question 18 of 25 1.0 Points Click to see additional instructions A Wendy's fast-food restaurant sells hamburgers and chicken sandwiches.On a typical weekday, the demand for hamburgers is normally distributed with a mean of 450 and standard deviation of 80 and the demand for chicken sandwiches is normally distributed with a mean of 120 and standard deviation of 30 , rounded to the must the restaurant stock to be 99% sure of not running out on a given day? Place you answer How many chicken sandwiches nearest whole number in the blank. For example, 345 would be a legitimate entry. ct ect

Explanation / Answer

solution=

Given:
Hamburgers sold daily are normally distributed and have a mean of 450 and standard deviation of 80, i.e. N(450,80).

Require:
Daily stock of hamburgers necessary in order not to run out 99 times out of 100.

Let X=number required, then we need
P(x>X)=0.99 which means
P(Z>(X-450)/80)>0.99
From normal distribution tables, Z=2.327,
solve for X
2.327=(X-450)/80
X-450=80*2.327=186.16
X=450+186.2=636.16

Answer:
636 hamburgers should be stocked.

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