CANT FIGURE OUT THE MAGNITUDE FOR PART A OR C PLEASE HELP Three spiders are rest

Question

CANT FIGURE OUT THE MAGNITUDE FOR PART A OR C PLEASE HELP

Three spiders are resting on the vertices of a triangular web. The sides of the triangular web have a length of a = 0.42 m, as depicted in the figure. Two of the spiders (S1 and S3) have +7.6 µCcharge, while the other (S2) has 7.6 µC charge.

(a) What are the magnitude and direction of the net force on the third spider (S3)?

(c) What are the magnitude and direction of the net force on the third spider (S3) when it is resting at the origin?

° counterclockwise from the +x-axis

Explanation / Answer

a)

= sin^-1(0.21/0.42) = 30 deg

F31=F32 = (9*10^9*(7.6*10^-6)^2)/(0.42^2) = 2.95 N

F31x = F31cos30 = 2.95cos30 = 2.55 N

F31y = - F31sin30 = -2.95sin30 = -1.48 N

F32x = F32cos30 = -2.95cos30 = -2.55 N

F32x = - F32sin30 = -2.95sin30 = -1.48 N

Fnetx = F31x+F32x = 2.55 -2.55 = 0 N I

Fnety = F31y + F32y = -1.48-1.48 = - 2.96 N j

Fnet = - 2.96 N j Directed downward along y axis

b)

F31=F32 = (9*10^9*(7.6*10^-6)^2)/(0.21^2) = 11.8 N

By the geometry of three charges x components are zero, hence Fnet = F32y + F32y = 2*F31= 2*11.8 = 23.6 N …………….Directed upward along y axis

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