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ake/questions/43652185 The University H3 H4 Linker H28 H2A H2B H2A Histone tale

ID: 142508 • Letter: A

Question

ake/questions/43652185 The University H3 H4 Linker H28 H2A H2B H2A Histone tale Hstone tale Figure A: Normal Figure B: Mutant Due to an error in meiosis, the gene for linker histone H1 got deleted in a mutant Caenorhabditis elegans (figure B). Suppose that the core histones bind to 145bp, the linker DNA covers 30 bp and the linker histone binds to additional 15bp of DNA, what will be the amount of DNA that is wrapped around the octamer and linker histone H1 in a normal worm (figure A) and what will be will be the amount of DNA wrapped around the nucleosome in the mutant Caenorhabditis elegans (figure B)? 145bp, 160bp 160bp. 175bp 175bp, 160bp 160bp. 145bp

Explanation / Answer

A) 145,160.

As we can see in the diagram, in the mutant dna no additional turn is made by dna around octamer. So bp will remain same.

As linker dna was binding 15bp more so they will be now added to nucleosome, so 145+15=160bp.

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