a. 0.01727_kg b. 0.01985_kg c. 0.01216_kg d. 0.01968_kg e. 0.01153_kg f. 0.01384

Question

a. 0.01727_kg b. 0.01985_kg c. 0.01216_kg d. 0.01968_kg e. 0.01153_kg f. 0.01384_kg The figure shows an m = 59-kg frictionless cylindrical piston (with diameter d = 11_cm) that floats on 1_mol of compressed gas at T_1 = 36degreeC. How far does the piston rise if the temperature is increased to T_2 = 420degreeC? 4. a. 276.2_cm b. 204.2.cm c. 393.7_cm d. 124.2_cm e. 166.6_cm f. 203.8_cm A(n) 90.0-kg student eats a 165-Calorie doughnut. To burn-it-off, he decides to climb the steps of a tall building. How high (in m) would he have to climb to expend an equivalent amount of work?

Explanation / Answer

Here ,

m = 59 Kg

diameter , d = 11 cm

number of moles , n = 1

T1 = 36 degree C

T2 = 420 degree C

Pressure = Pa + mg/(area)

Pressure , P = 1.01 *10^5 + 59 * 9.8/(pi * (0.11/2)^2)

P = 1.62 *10^5 Pa

let the initial height is h1

Using ideal gas equation

P * V1 = n * R* T1

1.62 *10^5 * pi * (0.11/2)^2 * h1 = 1 * 8.314 * (36 + 273)

h1 = 1.669 m

for the final height h2

Using ideal gas equation

P * V2 = n * R* T2

1.62 *10^5 * pi * (0.11/2)^2 * h2 = 1 * 8.314 * (420 + 273)

h1 = 3.742 m

change in height = h1 - h2

change in height = 3.742 - 1.669

change in height = 2.073 m

the correct option is b) 204.2 cm

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