A submarine dives to a depth of 181 feet in the ocean. What is the force (in pou

Question

A submarine dives to a depth of 181 feet in the ocean. What is the force (in pounds) acting on a hatch that has an area of 4.1 square feet?

WARNING: Do not use the information associated with any Figures in the chapter (round off errors). Do not consider atmospheric pressure in your calculation (the pressure inside of the submarine is maintained at 1 atmosphere, which offsets the 1 atmosphere of pressure that normally would be added to the gauge pressure). Do use the weight density form of the fluid pressure equation in order to work the problem in English units. This is a multi-step problem.

Explanation / Answer

force acting on a submerged particle = pho*g*A*h

where pho = density of the material in which it is immersed

A = surface area of the dive

h = depth of COG from the free end of the liquid

density of water in fps unit = 62.42796 pound/ft^3

value of g in fps = 32.2 ft/s

F = 62.42796 * 32.2 * 4.1*181

F = 1.49*10^6 pound

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