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A) If resitor R1 is 75 ohms and R2 is 200 ohms, what is the series resistance? B

ID: 1423006 • Letter: A

Question

A) If resitor R1 is 75 ohms and R2 is 200 ohms, what is the series resistance?

B) If the power supply is set at 6 volts, what are the voltage and current measured by the sensors in the series resistance set-up of Figure 6?

C) What is the voltage across R1? (Hint: V=IR)

D) What is the voltage across R2?

E) What is the sum of the voltages across R1 and R2?

F) What is the current into R1 (as measured by current sensor 1 in Figure 7 and Figure 8?)

G) What is the current into R2?

R1 R2 Figure 6. Schematic for measuring series resistance.

Explanation / Answer

A)
R1 and R2 are in series

Rnet = R1+R2
= 75 + 200
= 275 ohm

B)
V across R1 and R2 = 6 V

C)
I = V/Rnet
= 6 / (275)
= 0.0218 A

V across R1 = I*R1
= 0.0218*75
= 1.64 V

D)
V across R2 = I*R2
= 0.0218*200
= 4.36 V

E)
sum =- 1.64 + 4.36 = 6 V

F)
Current = 0.0218 A

G)
Current = 0.0218 A

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