treat the batteries as ideal and find the current in each se?si?s?to 5) The swit

Question

treat the batteries as ideal and find the current in each se?si?s?to 5) The switch in the circuit shown has been open for a very long time. At time t -0, The switch in t ecircuit shown has been open for a ver cong time. At time t=0, 5) the switch is closed. Find: a) the current through the 2 M2 resistor immediately after the switch i b) closed. the charge on the capacitor when it becomes fully charged. the current through the 2 M resistor after the capacitor is fully charged. After the capacitor is fully charged, the switch is opened d) What is the current through the 2 MS2 resistor immediately after the switch is opened? e) What is the charge on the capacitor 2 seconds later? How much energy is dissipated in the 2 M resistor in the first 2 seconds after the switch is opened? 2 N 3 V

Explanation / Answer

(a)
When the switch is open after a very long time,
Capacitor acts as a Short circut and all the current will pass through Capacitor,
Therefore,

Current through, 2M ohm Resistor, = 0

(b)
Q = C*V
Q = 6 * 3 uC
Q = 18 uC
Charge across the capacitor, Q = 18 uC

(c)
I = V/R
I = 3/(4+2)
I = 0.5 uA
Current through the Resistor, I = 0.5 uA

(d)
Voltage across the resistor,
V = Q/C
V = 18/6 = 3V

V = I*R
I = 3/(2*10^6)
I = 1.5 uA
Current through the Resistor, I = 1.5 uA

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