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Safari File Edit View History Bookmarks Window Help 5796 CAO, Thu Feb 25 1 1:16 AM a E ezto.mheducation.com Homework Chapter 18 College Physics With An Integrated Approach To Forces And Kinematics 4 Chegg.com 1 out of 1 attempt Assistance Check My Work Try Another View Hint View Question Show Me Guided Solution Practice This Question Print Question Help Report a Problem Part 1 (a) Choose the circuit showing how a voltmeter would be connected to measure the voltage across the 77.0-k resistor. 6.00 V 77.0 k 1.07 k A: 16.8 k 31.3 References EBOOK &Resources; EBOOK&Resources; Multipart Answer Difficulty:2 Chapter: 18- Electric Current Section: 09 - Measuring Currents and

Explanation / Answer

a)

If the voltmeter is not ideal and the resistance of the voltmeter volt= 2.3*10^6 ohm = 2300 kohm

net resistance of the circuit ,

Rnet = (77*2300/(77+2300) +16.8 ) || (1.07) + 31.3

So,

Rnet = (91.3 || 1.07)k +31.3

= (91.3*1.07/(91.3+1.07))k + 31.3

= 1.06k + 31.3

= 1.091 k ohm

So, Inet = 6/(1.091*10^3) = 5.5*10^-3 A

So, voltage across 1.07 kohm ,

V1 = 6 - 5.5*10^-3*31.3 = 5.828 V

So, current in 16.8 kohm = 5.5*10^-3 - (5.828)/(1.07*10^3)

= 5.33*10^-5 A

So, voltage across 77 kohm = 5.828 - 5.33*10^-5*16.8*10^3 =4.93 V

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