Thermodynamic system can proceed from state A to state B with two different proc

Question

Thermodynamic system can proceed from state A to state B with two different processes. For process 1, 50J of work is done on the system and 300J of heat is transferred to the system. For process 2, 50J of work is done BY the system on its environment. The internal energy of the system is by J (positive value). For process 2, J (positive value) of heat must be transferred the system. If the system is initially in state A, and process 1 is followed by the reverse of process 2, then the system will end up in and the net change in the internal energy of the system will be J. Furthermore, there will be net transfer of J (positive value) of heat the system and a net J (positive value) amount of work done the system.

Explanation / Answer

According to First law of thermodynamics,

Heat supplied to the system results in work done and increasing internal energy. also internal energy is a state function and does not depend on the path

for process 1&2 , internal energy INCREASES(1) BY 300-50 = 250 J (2)

For process 2 Work done =-50J , THerefore heat supplied = 200 J (3) TO(4) THE SYSTEM

If processes are 1 and 2 reverse occur. The system will be back to the orignal state (5). Therfore net change in internal energy is 0(6). Net heat of 300 -200 J ie 100J (7) WILL BE TRANSFER TO(8) THE SYSTEM. 50+50 ie 100 J(9) AMOUNT OF WORK WILL BE DONE ON (10) the system.

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