1. What are the magnitude and direction of the electric field at a distance of 2
ID: 1421410 • Letter: 1
Question
1. What are the magnitude and direction of the electric field at a distance of 2.50 m from a 90.0-nC charge?
2. Two point charges of +40.0 C and -10.00 C are separated by a distance of 10.0 cm. What is the intensity of electric field E midway between these two charges?
3. Three 3.0 C charges are at the three corners of an square of side 0.50 m. The last corner is occupied by a -3.0 C charge. Find the electric field at the center of the square
4. Q1 = 5.0 C is at (0.30 m, 0); Q2 = -2.0 C is at (0, 0.10 m); Q3 = 5.0 C is at (0, 0). What is the magnitude and direction of the Electric field on the 5.0 C charge? 2 D! MAG of E resultant &angle and do not use Coulombs law, E field equations only!
5. Four identical positive charges + q= 5uC are placed at the corners of a square of side L=10cm. Determine the magnitude and direction of the electric field due to them at the midpoint of one side of the square. HINT symmetry helps
Please I need the answers in details. thanks
Explanation / Answer
1. for a point charge, E= Kq/r2 = 9e+9 x 90e-9 /2.52= 810/6.25 = 129.6 N/C
2. following the same formula, but here are two charges and distance is half of 10cm,
E = 9e+9 x 40e-6 /0.052 - 9e+9 x ( -10e-6) /0.052= (9e+3 / 0.0025) x(40 +10)
= 50x9000 /0.0025 = 1.8e+8 = 1.8 x 108 N/C
3. two charges which are in opposite direction and equal will cancel out and two(one -3uC and other +3uC) will be left, and will sum up for electric field
E = 2 X 9e+9 x 3e-6 / (0.5/root2) 2 = 54 x e+3 / 0.125 = 54000 x 8 = 432000 N/C towards negative charge
4)E = E due to Q2 + E due to Q3
E due to Q2 = 9e+9 x -2 / (0.12+0.32) = -1.8e+11 at tan-1(1/)
= 1.8e+11 x 0.1/root (0.12+0.32) j -1.8e+11 x 0.3/root (0.12+0.32) i = 0.57e+11j - 1.71e+11i
E due to Q3 = 9e+9 x 5 / (0.32) = 5e+11 i
net E = 0.57e+11j - 1.71e+11i + 5e+11 i = 3.29e+11i + 0.57e+11j
= 3.34e+11 N/C at 9.8 degree with positive x-axis...tan-1 (57/329) =9.8 degree
Resultant E=
5) By symmetry all the electric fields will cancel out each other. So net Electric field is zero
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