PART TWO Provide step-by-step solutions to the following problems. Mind the unit
ID: 1421304 • Letter: P
Question
PART TWO Provide step-by-step solutions to the following problems. Mind the units. Ultrasound images can't show detail less than about one wavelength in sue. Can an ultrasound imager operating at 4.8 MHz resoh/c large kidney stones, assuming v = 1580 m/s? Justify your answer. An electric dipole lies on the x-axis, consisting of a -2.5 nC charge at x = -10.0 cm, and a +2.5 nC charge at +10.0 cm. Compute the electric field at the point (0,10.0 cm) on the y-axis. Draw a sketch of thc elcctric fields and make use of the symmetry of the problem. Use k = 9.0times10s N m2/C2 and recall that sin 45degree = cos 45degree = 1/V2. Leave V2 as a factor in all of your calculations. Suggested notation: E* for the electric field due to the positive charge, E- for the electric field due to the negative charge.Explanation / Answer
as we know, frequency*wavelength=speed of wave
==>wavelength=speed/frequency
=1580/(4.8*10^6)=3.2916*10^(-4) m
as kidney stone size is generally in mm range (and here we are taking about large size stones),
the ultrasound imager will be able to resolve the kidney stones as the size of stone is greater than wavelength of the unltrasound wave being used by the imager
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