net work Gone on the package 6.11 A 128.0-N carton is palled up a frictionless b
ID: 1421171 • Letter: N
Question
Explanation / Answer
Weight W = 128 N
theta = 30 degree
T = 72 N
a) Work done by the tension force = T*d = 72*5.2 = 374.4 J
b) Workdone by gravity force = -mg sin(theta)*d = -128*sin(30 deg)*5.2 = -332.8 J
c) The work done by the normal force is zero because the displacement is perpendicular to the force.
d) Net work done = 374.4 - 332.8 = 41.6 J
e) In this case the work done will be Tcos(theta1-theta2)*d = 72*cos(20 deg)*5.2 = 351.8 J
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