Two negative charges, Q = -50 C are placed on the x-axis at x = +0.5 m and x = -

ID: 1420272 • Letter: T

Question

Two negative charges, Q = -50 C are placed on the x-axis at x = +0.5 m and x = -0.5 m.

Part A

How much energy does it take to assemble these two charges?

Express your answer using three significant figures.

Part B

You place an unknown charge on the y-axis at y = 1 m and find that the electric potential is 0 V at the origin. What is the unknown charge?

Part C

If you place a -1 C charge at the origin, what is the x-component of the force on it from the other three charges?

Part D

If you place a -1 C charge at the origin, what is the y-component of the force on it from the other three charges?

Energy = J

A) the electrostatic potential energy U = kq1q2/r = (9*10^9*50*50*10^-12)/1 = 22.5 J

B) V = -kQ/0.5 - kQ/0.5 + kq/1 = 0 ====> -2Q + 0.5q = 0 ====> q = 4Q = -200 uC

C) Fx = (9*10^9*1*10^-6)[Q/0.5^2 - Q/0.5^2] = 0

D) Fy = (9*10^9*1*10^-6*200*10^-6)/1 = 1.8 N (-y-direction)

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.