An elevator is ascending at a constant velocity. A block of mass m is suspended

Question

An elevator is ascending at a constant velocity. A block of mass m is suspended from the ceiling of the elevator by a rope, as shown in the figure. Which of the following is true of the magnitude of the tension T in the rope? T = mg T mg T = 0 Now assume the elevator is accelerating upward with a constant non-zero acceleration. Which of the following is true of the magnitude of the tension T in the rope? T = mg T mg T = 0 Now assume the elevator is accelerating down with a constant non-zero acceleration. Which of the following is true of the magnitude of the tension T in the rope? T = mg T mg T = 0 Finally, assume the elevator is in "free-fall" (accelerating down with acceleration -9.8 m/s^2). Which of the following is true of the magnitude of the tension T in the rope? T = mg T mg

Explanation / Answer

1)

T - mg = ma

but V constant so a =0

T=mg

2)

T =mg+ma where a is +ve
T >mg

3)

mg - T = ma

T = mg-ma

T <mg

4)

mg -T= mg

T =0

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