A block with mass m = 5.00 Kg slides down a frictionless surface inclined 36.9 d

Question

A block with mass m = 5.00 Kg slides down a frictionless surface inclined 36.9 degree to the horizontal. A string attached to the block is wrapped around a flywheel on a fixed axis at O. The flywheel has a mass 25.0 Kg and moment of inertia 0.62 Kg middot m^2 with respect to the axis of rotation. The string pulls without slipping on the flywheel at a perpendicular distance of 0.200 m from the axis. The free-body diagram for the wheel is shown in Figure (b). Explain why the angle shown for the normal force is correct in this situation. What is the acceleration of the black down the ramp in m/s^2 to two decimal places? What is the tension in the string in N to two decimal places?

Explanation / Answer

Ans 1) from the figure b, it can be seen that wheel is rotating in clockwise direction keeping in mind the direction of Tension T and hence the angle shown in the figure is correct for the situation.

3) Tension T = mgsin36.9 = 5 * 9.8 * sin36.9 = 29.42N

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