?A charge + q is at the origin. A charge -2 q is at x = 4.10 m on the + x axis.

Question

?A charge +q is at the origin. A charge -2q is at x = 4.10 m on the +x axis.

(a) For what finite value of x is the electric field zero?

(b) For what finite values of x is the electric potential zero? (Note: Assume a reference level of potential V = 0 at r = ?.)

Smallest value of x:

Largest value of x:

FYI : (There should be three answers)

12./3 points .:..013 points 1 Answers 12. A charge +d s atrpe 2a 420m on thex akis. (alForl what finite value ofi the electric field zero? Your response differs from the correct answer by more than 10%. Double check your calculations. reepense differs from (b) For what finite alue the electric potential zero (Note: Assume a reference level of potential V= 0 a ) Smallest value of x Largest value of g Your response differs from the correct answer by more than 10%, Double check your calculations. Need Help? Readtll on Submit Answer …Save res nother Version Submit Assignment Save Assignment Progress Home My Assignments Extension Request WebAssign 4.01997 2016 Advanced Instructional Systems, Inc. All rights reserved O Ask me anything

Explanation / Answer

q1 = +q

q2 = -2q

let electric field is zero at a distance x to the left from +q charge.since E.F is zero, E1 = E2

k*q1 / x2 = k*q2 / (4.10+x)2

k*q / x2 = k*(2 q) / (4.10+x)2

2*x2 = ( (4.10+x)2

on solving, x2 -8.2 x-16.81 = 0

on solving this equation , x = 9.895m

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b) i) let electric potential is zero at a distance x to the left of +q charge.[ potential = k*q / r]

k*q / x = k*2q / ( x+4.10)

x = 4.10 m ( to left of +q charge)

ii) let x will be right of +q charge at which potential is zero

k*q/x = k*2q / 4.10 - x

2x = 4.10 - x

x = 1.367 m to right of +q charge.

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