A 10kg mass is attatched to a spring and the spring stretches. The potential ene

Question

A 10kg mass is attatched to a spring and the spring stretches. The potential energy stored in the spring is 100J. If we remove the 10kg mass and replace it with a 20kg mass, how much potential energy is now stored in the spring? (Answer is 399.7J show work) A 10kg mass is attatched to a spring and the spring stretches. The potential energy stored in the spring is 100J. If we remove the 10kg mass and replace it with a 20kg mass, how much potential energy is now stored in the spring? (Answer is 399.7J show work)

Explanation / Answer

mass m1=10 kg

potential energy stored P.E1=100 J

the equation of potential energy in oscillation =>P.E=1/2m1w^2x^2

100=1/2 *10*w^2x^2

(wx)^2=20.......................................(1)

we know that the mass is replace by another mass 20 kg

so the new potential energy in the string =mw^2x^2=20*20=400 kg

therefore the new potential energy =400 kg

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