The beam is subjected to a load F = 400 N and is supported by the rope and smoot

Question

The beam is subjected to a load F = 400 N and is supported by the rope and smooth surfaces at A and B. Let the tension in the rope be T, and normal forces at A and B be N_A and N_B, respectively. (Figure 1) Neglecting the weight of the beam, draw the free-body diagram of the beam, and select the correct equilibrium equation along the y direction. sigma F_y= N_A cos45degree + N_B cos30degree -T -400 sigma F_y= N_A sin45degree + N_B sin30degree -T -400 sigma F_y =N_A+N_B -T -400 sigma F_y= N_A sin45degree + N_B sin30degree + T -400 sigma F_y =N_A+N_B + T -400 sigma F_y= N_A cos45degree + N_B cos30degree + T -400

Explanation / Answer

Part A)    Here,   For equilibrium

=>    NAcos45 + NBcos30 =   T   +   F

=>          NAcos45 + NBcos30 =   T   +   400

=>      Fy = NAcos45 + NBcos30 - T   - 400

=> option (1) is correct .

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