1/ How many coulombs are transferred in two seconds by a current of two amperes?

Question

1/ How many coulombs are transferred in two seconds by a current of two amperes?

3 c

1 c

4 c

2 c

2/ In Millikan's oil-drop experiment, which of the following could NOT be the net charge on the oil drop?

1.6 × 10-19 C

0.5 × 10-19 C

4.0 × 10-18 C

4.8 × 10-19 C

3/ The surface of any conductor is an equipotential surface.

True

False

4/ Two protons are 1 cm apart. The electric force of repulsion between them is much greater than the gravitational attraction between them.

True

false

5/ A rubber rod cannot have a net charge because it is an insulator.

True

False

6/The electric potential in the vicinity of a number of charges is equal to the algebraic sum of the potentials due to each charge.

True

False

1.6 × 10-19 C

0.5 × 10-19 C

4.0 × 10-18 C

4.8 × 10-19 C

Explanation / Answer

1.
we know that from the formula Q = i*t ===> Q = 2 A * 2 s = 4 C
so
Four coulombs are transferred in two seconds by a current of two amperes

2. In Millikan's oil drop experiment the charge of oil drop is multiples of charge of electron so from the given options the

   0.5 × 10-19 C,0. 5 × 10-19 C are not multiples of 1.6*10^-19 C

3.
   The surface of any conductor is an equipotential surface is True

4.
   Two protons are 1 cm apart. The electric force of repulsion between them is much greater than the gravitational attraction between them.
   True
   because gravitational force is the weakest force in the universe.
   F_e = k q1*q2 /r^2, F_g = Gm1*m2/r^2

   if we substitute the values we get F_g is less than F_e

5.   A rubber rod cannot have a net charge because it is an insulator.
   True

6.    The electric potential in the vicinity of a number of charges is equal to the algebraic sum of the potentials due to each charge.
   True

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