please show all work so i can follow it and see how you took down this beast. (1

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please show all work so i can follow it and see how you took down this beast.

(10%) Problem 8: Four charges of equal magnitude Q = 35 nC are placed on the corners of a rectangle of sides Di21 cm and D2-5 cm. The charges on the left side of the rectangle are positive while the charges on the right side of the rectangle are negative. For this problem, use the coordinate system and angle indicated HQ 2 +Q D ©theexpertta.com 14% Part (a) Which of the following represents a free-body diagram for the charge on the lower left hand corner of the rectangle? 14% Part (b) Write an equation for the net horizontal force acting on the charge located at the lower left corner of the rectangle in terms of the magnitude of the forces from the three other charges, Fi, F2, F3, and the angle . 14% Part (c) Calculate the numeric value for the horizontal force, in newtons. 14% Part (d) Write an equation for the net vertical force acting on the charge located at the lower left corner of the rectangle in terms of the magnitude of the forces from the three other charges, F1, F2, F3, and the angle . -| 14% Part (e) Calculate the numeric value for the vertical force, in newtons. - 14% Part (f) Calculate the magnitude of the net force on the charge located at the lower left corner of the rectangle, in newtons. × 14% Part (g) Calculate the angle, in degrees counterclockwise with respect to the positive x-axis, of the net force.

Explanation / Answer

numerical value of horizontal force = 8.98 * 109 * (35 * 10-9)2 * (1/0.212 + cos45/0.21582)

                                                        = 4.164 * 10-4 N

equation of vertical force =   kq2 * (1/d22 + sin45/dv2)

=>   numerical value of vertical force = 8.98 * 109 * (35 * 10-9)2 * (- 1/0.052 + sin45/0.21582)

                                                          = - 4.233 * 10-3 N

=>   magnitude of net force =    4.253 * 10-3 N

=>    angle =    360 - tan-1(4.233/0.4164)

                  =    275.618 degree

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