a car is parked on a cliff overlooking the ocean on an incline that makes an ang

Question

a car is parked on a cliff overlooking the ocean on an incline that makes an angle of 19 below the horizontal. The negligent driver leaves the car in neutral and the emergency brakes are defective. The car rolls from rest down the incline with a constant acceleration of 3.06m/s^2 for a distance of 65.0m to the edge of the cliff, which is 50.0m above the ocean. (a) find the cars position relative to the base of the cliff when the car lands in the ocean (b) find the length of time the car is in the air

Explanation / Answer

(a) ans

angle =19

acceleration a=3.06 m/s^2

inclination to the edge of the cliff =>AC=65 m

height BC=50 m

the cars position relative to the base of the cliff when the car lands in the ocean =>AB=

AB^2=AC^2-BC^2

=65^2-50^2=4225-2500=1725

AB=[1725]^1/2=41.53 m

(b) ans

firstly we find the velocity of the car

V^2-u^2=2as sin(theta)

0-u^2=2*3.06*65 sin(19)

u^2=129.511

the velocity of the car moving =11.4 m/s

therefore the length of time the car is in air =>T=S/u=65/11.4=5.702 sec

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