A composite slab has dimensions of d 1 = 11.0 cm, d 2 = 2.80 cm, and d 3 = 13.0

Question

A composite slab has dimensions of d1 = 11.0 cm, d2 = 2.80 cm, and d3 = 13.0 cm. Half the slab consists of aluminum (? = 2.70 g/cm3) and half consists of iron (? = 7.85 g/cm3). Determine the location, in unit vector notation, of the center of mass of the slab ((Please make it readable with steps ))

A composite slab has dimensions of d1 = 11.0 cm, d2-2.80 cm, and a 3 = 13.0 cm. Half the slab consists of aluminum ( 2.70 g/cm3) and half consists of iron (p = 7.85 g/cm3). Determine the location, in unit vector notation, of the center of mass of the slab. d. Iron -Midpoint Aluminum

Explanation / Answer

given

d1 = 11.0 cm,

d2 = 2.80 cm,

and d3 = 13.0 cm.

aluminum ( = 2.70 g/cm3)

iron ( = 7.85 g/cm3)

Xcm = 13 / 2

Xcm = 6.50 c m

and

Zcm = 2.80 / 2

Zcm = 1.40 cm

Ycm = Mfe(d1/2)+ Mai(3d1/2) / Mfe + Mal

Ycm = 8.31 cm

the center of mass is

( Xcm , Ycm , Zcm ) = ( - 6.50 , 8.31 , 1.40 ) cm

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