Nuclear Binding Energy: : Calculate the mass defect of the nitrogen nucleus^n_7N

Question

Nuclear Binding Energy: : Calculate the mass defect of the nitrogen nucleus^n_7N. The mass m_N of neutral^n_7N is equal to 14.00307 atomic mass unit Part B: Calculate the binding energy E_B of the nitrogen nucleus^n_7N. Part D: Calculate the mass defect of the helium^H_2He. The mass of^H_2He is given by m_He = 4.002603u Part C: Calculate the binding energy per neutron of the nitrogen nucleus^n_7N Part E: Calculate the binding energy E_B of the helium nucleus^H_2He Part F: Calculate the binding energy per nucleus of the helium nucleus^H_2He.

Explanation / Answer

Part A) mass defect of nitrogen =   0.00307 amu

Part B) Binding energy of nitrogen = 0.00307 * 1.66 * 10-27 * (3 * 108)2

                                                                                  = 2.8666 MeV

Part D) mass defect of helium = 0.002603 amu

Part C)     Binding energy per nucleon of nitrogen = 0.00307 * 1.66 * 10-27 * (3 * 108)2/14

                                                                                 = 0.2047 MeV

Part E)     Binding energy of helium = 0.002603 * 1.66 * 10-27 * (3 * 108)2

                                                                                  = 2.4305 MeV

Part F)    Binding energy per nucleon of helium = 0.002603 * 1.66 * 10-27 * (3 * 108)2/4

                                                                                = 0.6076 MeV

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