Now, three masses (m1-4.4 kg, m2 -13.2 kg and m 8.8) hang from three identical s
ID: 1778412 • Letter: N
Question
Now, three masses (m1-4.4 kg, m2 -13.2 kg and m 8.8) hang from three identical springs in a motionless elevator. The springs all have the same spring constant given above. What is the magnitude of the force the bottom spring exerts on the lower mass? You currently have 1 submissions for this question. Only 10 submission are allowed You can make 9 more submissions for this question. "What is the distance the middle spring is stretched from its equilibrium length? You currently have 2 submissions for this question. Only 10 submission are allowed You can make 8 more submissions for this question. 4) Now the elevator is moving downward with a velocity of v "-2.8 m/s but accelerating upward at an acceleration of a . 4.8 m/s. (Note: an upward acceleration when the elevator is moving down means the elevator is slowing down.) What is the magnitude of the force the upper spring exerts on the upper mass? You currently have O submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question SWhat is the distance the lower spring is extended from its unstretched length? cm You currently have O submissions for this question. Only 10 submission are allowed You can make 10 more submíssions for this question. Finally, the elevator is moving downward with a velocity of v-3.7 m/s but accelerating downward at an acceleration of a·-1.7 m/ Compare the magnitude of the NET force on each mass: You currently have 2 submissions for this question Only 10 submission are allowed. You can make 8 more submissions for this question what is the magnitude of the net force on the middle mass? You currently have O submissions for this question. Only 10 submission are allowed. You can make 10 more submíssions for this question.Explanation / Answer
2) Force = m3g = 8.8*9.8 = 86.24 N
For remaining parts, spring constant k is required
3) x = F2/k = ( 86.24+13.2*9.8)/k = 215.6/k where k spring constant
4) Force exerted by top spring on top block
= (m1+m2 +m3) *(g+a) = (4.4+8.8+13.2)*(9.8+4.8)
= 385.44 N
5) lower spring extension x= m3(g+a) /k = 8.8*(9.8+4.8)/k = 128.5/k
6) F2 > F3 > F1
7) net force on middle = m3a = 13.2*4.8 = 63.36 N
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